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# WAEC GCE 2017 MATHEMATICS ANSWERS

**100% VERIFIED MATHEMATICS OBJ ANSWERS**

1–10 CBACDBBDCA

11–20 ACCBDADBDC

21–30 BCADDABDAC

31–40 DACBBDACCD

41–50 ACCBDABBCD

**100% VERIFIED MATHEMATICS THEORY ANSWERS**

PLS NOTE THIS SYMBOLS

^ means Raise to power

* means multiplication

sqrt or root means Sqr root

/ means division or divide

degree means degree sign that looks like small zero

tita means tita sign that looks like crossed-zero

IGNORE ALL ANSWERS POSTED HERE PREVIOUSLY; THE PAPER WAS CHANGED DUE TO EXCESSIVE LEAKAGE. WE ARE SOLVING THE NEW[REAL ONE]. Relax!!!

**ANSWERS**

(1a)

[2whole1/2+1whole3/4/1whole2/5)]/[2whole1/4)-1whole1/2)]

[5/2+7/4/7/5]/[9/4-3/2]

=[5/2+7/4*5/7]/[9/4-3/2]

[5/2+5/4]/[9/4-3/2]

=[(10+5/4)/(9-6/4)]

=(15/4)/(3/4)

=15/4*4/3

=5

(1b)

From tan60/1*PR/3√2

PR=3√2*1/√3

=3√2/√3*√3/√3

=3√6/3=√6

From sin45/1*√6/x

x=√6*√2

=√12

=√4*3

=2√3

==================================

2a)

A=p(1+r/100)^n

A=2205000

n=2

r=5%

p=?

2205000=p(1+5/100)^2

2205000=p(1.05)^2

p=2205000/(1.05)^2

p=N2,000,000

(2b)

Area=30cm^2,

h/b=3/2

Area=1/2bh

b=2h/3

30=1/3*2h/3*h

2h^2=30*2*3

h^2=30*2*3/2

h^2=9

h=√9

h=9.49m

========================

(3)

2x/1-2/5y=2y/1(isosceles angle)

LCM = 5

10x-2y=10y

10x=10y+2y

x=12y/10

x=6y/5……(1)

2x-2/55y+2whole1/4c+1/2+2y=180(sum of angle in a triangle)

2x/1-2y/5+(9/4)x+y/2+2y=180

LCM = 20

40x-8y+45x+10y+40y=3600

40x+45x-8y+50y=3600

95x+42y=3600….(2)

Substitute for x in eq…2

95(6y/5)+42y=3600

19(6y)+42y=3600

114y+42y=3600

156y/156=3600/156

y=23.08

Subst for y in equ…1

x=6(23.08)/5

x=27.69

=============================

(4)

OSP+OSR=90

44+OSR=90

OSR=90-44=46

But OSR+RSP=180

46+RQP=180

RQP=180-46

RQP=134°

===========================

5b)

Median = ((N + 1) / 2)th item

Where:

N = 31

40, 40, 40, 40, 40, 40, 40, 41, 41, 41, 41, 42, 42, 42, 42, 42, 42, 43, 43, 44, 44, 44, 44, 45, 45, 46, 46, 46, 46, 46, 46

Data table

F 7 4 6 2 4 2 6

X 40 41 42 43 44 45 46

Median = ((31 + 1) / 2)th item

Median = (32 / 2)th item

Median = 16th item

Arranging the discrete data in ascending order, We go get:

40, 40, 40, 40, 40, 40, 40, 41, 41, 41, 41, 42, 42, 42, 42, 42, 42, 43, 43, 44, 44, 44, 44, 45, 45, 46, 46, 46, 46, 46, 46

Median = 42

===============================

(7a)

Log6y+2log6x= 3

Log6y+log6x²= 3

Log6(x²y)= 3

X²y = 6³

X²y = 216

Y= 216/x²

(7b)

(I). Percentage who liked football and volleyball but not boxing = 20

(II)

Percentage who liked exactly two sports = 40 + 20 + 10 = 70

(III)

Summing

5+5+10+40+20+10+5+x = 100%

X + 95 = 100

X = 100– 95 = 5%

Percentage who like none= 5%

================================

9a) Diagram

(9b)

a= 360-330{ =030°

b=a=030°{alternate angles}

Φ = 090°+030°

= 120degree

(i) find distance AC wing.

|AC|²= |BC|²+|AB|²–2|AB||BC|Costita

|AC|²= 300²+100²–2(300)(100)Cos120degree

= 90000+10000–60000×(-0.5)

=100,000+30,000

= 130,000

|AC| = √130,000 = 360.555KM

=360.56Km(2d.p)

(ii)

find β, applying the first rule

300/Sinβ = 360.56/Sin120

Sinβ = 300sin120/360.56 = 259.81/360.56

= 0.7206

β = sin inverse(0.7206)

= 46°

Therefore the bearing of the plane from A

=330–046

=284°.

============================

11)

A={4,5,6,7,8,9,10,11,12}

B={10,11,12,13,14,15,16,17,18,19,20,21,22,23,24}

M={4,8,12,11,6,20,24,28}

a)prob (A)=3/7

b)prob( B)=7-4/7=3/7

c)prob(AuB)=n(AuB)/n(m)

but (AuB)={4,8,12,11,6,20,24,}

prob(AuB)=6/7

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